SIBA

SIBA MDCAT 2025 past paper, Version C

The real paper set in Sindh for MDCAT 2025. Below are its key facts and 10 of its questions, answered and explained.

The paper at a glance

Questions
180
Marks
180
Time allowed
3 hours
  • Bio 81 · Chem 45 · Phy 36 · Eng 9 · LR 9
  • 3 hours, no negative marking
  • Sindh's first paper set by SIBA Testing Services

10 questions from this paper

Real questions, taken from across the paper in the order they were printed. Pick your answer before you open the explanation, or it teaches you nothing.

Question 1 · Biology

Overconsumption of which of the following foods increases the risk of calcium oxalate stone?

  1. ALeafy vegetables
  2. BFruits contain Vitamin C
  3. CFruits contain high fiber
  4. DWhole grains
Show the answer and explanation

Answer: A. Leafy vegetables

Leafy vegetables like spinach and rhubarb are high in oxalates, which can bind with calcium in the body to form calcium oxalate stones. While other options like fruits rich in Vitamin C or fiber, and whole grains, are generally healthy, they don't pose the same risk for calcium oxalate stone formation as high-oxalate foods.

Question 18 · Biology

Which of the following is a characteristic of a non-competitive enzyme inhibitor?

  1. ABinds to the enzyme active site
  2. BCan be overcome by increasing substrate concentration
  3. CIncreases the speed of the reaction
  4. DPoint of action is allosteric site
Show the answer and explanation

Answer: D. Point of action is allosteric site

A non-competitive inhibitor binds to a site on the enzyme different from the active site, known as an allosteric site. This binding changes the enzyme's shape, reducing its ability to catalyze the reaction, regardless of substrate concentration. Option A is incorrect because competitive inhibitors bind to the active site. Option B is incorrect because non-competitive inhibition cannot be overcome by increasing substrate concentration. Option C is incorrect as inhibitors slow down reactions.

Question 36 · Biology

If the disease is caused due to a defective gene located on the X chromosome, then defectives gene can only be transmitted to male offspring by the:

  1. AFemale gamete
  2. BMale gamete
  3. CBacteria
  4. DMutation
Show the answer and explanation

Answer: A. Female gamete

The defective gene is on the X chromosome. Females have two X chromosomes (XX), so they can carry the defective gene and pass it to their sons via their egg (female gamete). Males have one X and one Y chromosome (XY); they pass their Y chromosome to their sons, so they cannot transmit an X-linked defective gene to their male offspring.

Question 54 · Biology

A student observes a microorganism under a microscope that lacks a nucleus and is made of a single cell. Which classification would best fit this organism?

  1. AUnicellular prokaryote
  2. BUnicellular eukaryote
  3. CMulticellular eukaryote
  4. DMulticellular prokaryote
Show the answer and explanation

Answer: A. Unicellular prokaryote

The organism is unicellular because it is made of a single cell. It lacks a nucleus, which is a defining characteristic of prokaryotes. Therefore, it is best classified as a unicellular prokaryote. Option B is tempting because it is unicellular, but it incorrectly suggests the presence of a nucleus.

Question 72 · Biology

Which of the following best describes the direction of impulse traveling in a typical neuron?

  1. AAxon ....... dendrite ...... cell body
  2. BDendrite ..... cell body ...... axon
  3. CSynapse ..... axon ...... dendrite
  4. DCell body ..... dendrite ...... axon
Show the answer and explanation

Answer: B. Dendrite ..... cell body ...... axon

The correct answer is B because nerve impulses, or action potentials, are initiated in the dendrites, travel to the cell body, and are then transmitted away from the cell body along the axon. Option A is incorrect because impulses do not travel from the axon to the dendrite.

Question 90 · Chemistry

Value of electronegativity of atoms A and B are 1.20 and 4.0 respectively, the percent ionic character will be:

  1. A43%
  2. B50%
  3. C55%
  4. D73%
Show the answer and explanation

Answer: D. 73%

The percent ionic character can be calculated using

Question 108 · Chemistry

During Clemmenson reduction of aldehyde and ketone, carbonyl group into alkane group is carried out with:

  1. AH₂ and Pd
  2. BLiAlH₄
  3. CZn/Hg conc.HCl
  4. DNH₂-NH₂/KOH
Show the answer and explanation

Answer: C. Zn/Hg conc.HCl

Clemmensen reduction specifically uses zinc amalgam (Zn/Hg) in concentrated hydrochloric acid (HCl) to reduce carbonyl groups of aldehydes and ketones to alkanes. Lithium aluminum hydride (LiAlH₄) is a strong reducing agent but typically reduces carbonyls to alcohols, not alkanes. Similarly, the Wolff-Kishner reduction (option D) also converts carbonyls to alkanes but uses a different set of reagents. Hydrogenation with H₂ and Pd (option A) usually reduces carbonyls to alcohols or alkenes, depending on the substrate and conditions.

Question 126 · Chemistry

Which carbonyl carbon is more electrophilic:

  1. AHCOOH
  2. BHCHO
  3. CCH₃COCH₃
  4. DCH₃COOH
Show the answer and explanation

Answer: B. HCHO

The carbonyl carbon in formaldehyde (HCHO) is the most electrophilic because it is bonded to two hydrogen atoms, which are weakly electron-donating. This results in a greater partial positive charge on the carbonyl carbon compared to other options. Acetic acid (CH₃COOH) is less electrophilic due to the electron-donating effect of the methyl group and the resonance stabilization involving the -OH group.

Question 145 · Physics

A gas expands from 1 m³ to 3 m³ at constant pressure of 2 Pa. Work done is:

  1. A2J
  2. B4J
  3. C6J
  4. D8J
Show the answer and explanation

Answer: B. 4J

The work done by a gas at constant pressure is calculated by the formula W = PΔV, where P is the constant pressure and ΔV is the change in volume. In this case, P = 2 Pa and ΔV = 3 m³ - 1 m³ = 2 m³. Therefore, W = (2 Pa)(2 m³) = 4 J. Option A is incorrect because it doesn't account for the full change in volume.

Question 163 · English

The board will approve the budget only after the auditor verifies the accounts. The most appropriate passive voice for the given sentence is:

  1. AThe budget will be approved by the board only after the accounts are verified by the auditor.
  2. BThe budget is approved by the board only after the accounts have been verified by the auditor.
  3. CThe budget is being approved by the board only after the accounts are verified by the auditor.
  4. DThe budget has been approved by the board only after the accounts were verified by the auditor.
Show the answer and explanation

Answer: A. The budget will be approved by the board only after the accounts are verified by the auditor.

Option A correctly transforms the active voice to passive voice while maintaining the original tense and meaning. The future tense "will approve" becomes "will be approved" and "verifies" becomes "are verified," accurately reflecting the conditional and future nature of the original sentence. Option B incorrectly changes the tense from future to present ("is approved").

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